CAT Percentile Calculation Method has been announced by IIM Kozhikode for CAT 2019. Let us have a detailed step by step look at CAT Percentile Calculation Method. We do hope that your **CAT Preparation** is going all good, and all those who are starting late are preparing from **CAT Crash Course**.

**CAT Percentile Calculation Method **

**4 Steps of CAT Percentile Calculation**

Illustration below is taken for Quant section (QA).

**Step 1:** Calculate the total number of candidates (N) who appeared for CAT (i.e. including both morning and afternoon sessions).

**Step 2:** Assign a rank (r), based on the scaled scores obtained in the QA section, to all candidates who appeared for CAT. In the case of two or more candidates obtaining identical scaled scores in the QA section, assign identical ranks to all those candidates.

**Illustration**

As an illustration suppose exactly two candidates obtain the highest scaled score in the QA section, then both of those candidates are assigned a rank of 1. Moreover, the candidate(s) obtaining the second highest scaled score in the QA section are assigned a rank of 3 and so on.

**Step 3:** Calculate the percentile score (P) of a candidate with rank (r) in the QA section as: P=((N-r)N)x100.

**Step 4:** Round off the calculated percentile score (P) of a candidate up to two decimal points.

**Example**

For example, all percentile scores greater than or equal to 99.995 are rounded off to 100, all percentile scores greater than or equal to 99.985 but strictly less than 99.995 are rounded off to 99.99 and so on.

**Similar Method for Overall & Other Sections’ Percentile**

A methodology similar to the one described above is used for the computation of the overall CAT percentile scores and for the percentile scores of other sections.

**Fairness and Equity in Percentile Calculation**

CAT Exam Centre has declared “In order to ensure fairness and equity in comparison of performances of the candidates across different test sessions, the scores of the candidates shall be subjected to a process of Normalization. The Normalization process to be implemented shall adjust for location and scale differences of score distributions across different forms and the scaled scores obtained by this process shall be converted into percentiles for purposes of shortlisting.”

Career Anna** CAT 2019 Percentile Predictor** will be live based on above methodology from October 2, 2019 for you to check basis your CAT Mock scores of TIME, IMS, CL and Career Anna.

**Normalization in CAT would be done as per following formula**

The score normalization process formula, as understood by CAT expert would be as follows-

Normalized mark (︿*M _{ij}*) of

*j*

^{th}candidate in

*i*

^{th}slot, is given by

︿

*M*=

_{ij}*M*–

^{g}_{t}*M*–

^{g}_{q}M_{ti}*M*(

_{iq}*M*–

_{ij}*M*) +

_{iq}*M*

^{g}_{q}where,

*M _{ij}* is the actual marks obtained by the

*j*

^{th}candidate in the

*i*

^{th}slot,

*M ^{g}_{t}* is the average marks of the top 0.1 % candidates in all slots,

*M ^{g}_{q}* is the sum of mean and standard deviation of marks of all candidates in all slots,

*M _{ti}* is the average of marks of top 0.1 % candidates in the

*i*slot,

^{th}*M _{iq}* is the sum of mean and standard deviation of marks of all candidates in the

*i*slot.

^{th}**Application of Formula in CAT – Example**

Total Test takers = 2,00,000

slots = 2

Test takers in each slot = 1,00,000 [ .1% of it = 100]

*M _{ij}* =

**170**out of 300 ( is the actual marks obtained by the

*j*

^{th}candidate in

the *2nd* slot)

*M ^{g}_{t}* = [195 + 190 ]/2 = 192 ( is the average marks of the top 0.1 % candidates of

both the slots)

here, 195 and 190 are the average of the top .1% aspirants of all slots

*M ^{g}_{q}* = 112 (is the sum of mean and standard deviation of marks

of all candidates in both the slots)

*M _{ti }* = 190 (is the average of marks of top 0.1 % candidates in

the *2nd* slot)

*M _{iq }* = 110 (is the sum of mean and standard deviation of marks

of all candidates in the *2nd* slot.)

So, according to the given formula, normalized score = (192-112)(170-110)/(190-110) + 112 = 172

**Expect high percentile with good scores**

The above score is supposed to fetch a percentile near about 99.05. Besides the introduction of Non-MCQ type questions without any penalty for wrong answers, it is expected that the candidates would score high and would record higher percentile.

Earlier all the questions used to be of MCQ type and due to negative marking system the percentile got dipped low in earlier CAT exams. Now with more questions available most of the candidates who refrained from attempting doubtful and difficult type of questions can expect a high percentile.